The question is what is f(1) when f(x)= |x – 4| + 5?

Before we start, I want to mention that this function involves the absolute value. The absolute value is when a number is being described as the distance away from the number 0 on a line. When it comes to absolute values, the number is never a negative.

Fore example, |5| = 5, |-235| = 235

So let us go straight into the problem!

f(1)= |(1) – 4| + 5

f(1)= |(-3)| + 5

f(1)= 3 + 5

f(1)= 8

There you go! When we put in an x-value of 1 into the function we will get 8 as the output or outcome!

## Answers ( )

Answer:8Step-by-step explanation:you substitute (x) with 1 so the equation would look like this

f(x)=|1-4|+5 so the answer for this is 8 because 1-4 is 3 and 3+5 is 8

Answer:Step-by-step explanation:The question is what is f(1) when f(x)= |x – 4| + 5?

Before we start, I want to mention that this function involves the absolute value. The absolute value is when a number is being described as the distance away from the number 0 on a line. When it comes to absolute values, the number is never a negative.

Fore example, |5| = 5, |-235| = 235

So let us go straight into the problem!

f(1)= |(1) – 4| + 5

f(1)= |(-3)| + 5

f(1)= 3 + 5

f(1)= 8

There you go! When we put in an x-value of 1 into the function we will get 8 as the output or outcome!